Engine : Electricity - 1117/1386
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| « Previous Question |
| A 440/110 V single phase transformer supplies a load of 5 kW at 0.8 power factor load. What will be its primary current? |
| A) 45.45 A |
| B) 56.82 A |
| C) 14.2 A |
| D) 11.36 A |
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| Comments |
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| scrubbyj427 - 2021-02-10 18:46:27 Member (7) |
| Thank you DRACOPOLIS |
| dracopolis - 2021-01-30 02:47:22 Member (5) |
| P = 5000 W (5kW), V = 440 V, Load Factor = 0.8, P = I*V*Load Factor 5000 = I*440*0.8 I = 5000/(440*0.8) = 14.2 A |
| scrubbyj427 - 2021-01-29 15:05:09 Member (7) |
| can someone show the math to this? |
| Stan - 2019-04-29 13:50:01 Registered (4) |
| P=I*U*load factor Correct answer is 14.2A |
| maritimesailor - 2015-10-08 00:31:25 Member (4) |
| I believe this answer is 11.36A |