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| Posted: 22 Dec 2014 10:11 UTC | Post #1 |
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| sailorpip Deck & Engine |
Registered Total Posts: 4 |
| I'm a little confused by the wording of this, as it is a series/parallel circuit. I've tried to work this down as follows: R1 = 10 Ohms. Because R2 and R3 are two resistors in parallel of the same value, I half the value without having to do all the reciprocal maths... R2+R3 = 5 Ohms. Add the two together (in series) = 15 Ohms (Total). Calculate current: 30 (Vt) / 15 (Rt) = 2 Amps (Total) Now, to calculate voltage: 10 (R1) / 15 (Rt) = .66 * 30 (Vt) = 20 (Voltage @ R1) 5 (R2&3) / 15 (Rt) = .33 * 30 (Vt) = 10 (Voltage @ R2&3) So... R1 Voltage x 2 Amps = 40 Watts R2&3 Voltage x 2 Amps = 20 Watts So I suppose I answered my own question. There being no 20 Watt answer, it must be referring to the power at R1. Hope you don't mind my spamming up the forum with this but I might need to review the formulas here after I spill coffee all over my personal notes on the table! |
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