
| Engine : Electricity - 185/1386 |
|---|
| « Previous Question |
| How is the power dissipated as heat in a direct current circuit calculated? |
| A) E divided by I |
| B) I times R divided by T |
| C) I squared times R |
| D) P divided by R |
loading answer...
| Comments |
|---|
| - (0) |
| <a href="https://www.google.com/">google</a> --- BBCODE --- --- RARE --- [link=https://www.google.com/]google[/link] [link name=google]https://www.google.com/[/link] ((https://www.google.com/)) ((https://www.google.com/ google)) [https://www.google.com/ google] [[https://www.google.com/ google]] [L=google]https://www.google.com/[/L] "google":https://www.google.com/ [google](https://www.google.com/) |
| - (0) |
| I’ve been studying DC circuits and got a bit stuck on how heat loss is actually calculated. I know it relates to current, voltage, and resistance, but applying the formulas in real situations is confusing. While working through calculations, I like using tools such as https://zinses-zinsrechner.de/ to better visualize how values change and relate to each other. It makes complex calculations easier to grasp. |
