Deck : General Navigation - 7/2138
|
|---|
| « Previous Question |
| The Light List indicates that a light has a nominal range of 8 miles and is 48 feet(14.6 meters) high. If the visibility is 6 miles and your height of eye is 35 feet(10.7 meters), at what approximate distance will you sight the light? |
| A) 12.4 nm |
| B) 5.9 nm |
| C) 8.0 nm |
| D) 15.0 nm |
loading answer...
| Comments |
|---|
| jkorkin - 2022-07-27 08:42:28 Member (19) |
| D = 1.17 SQRT(Ho) + 1.17 SQRT(Hi) |
| trishamm - 2022-01-18 13:13:11 Registered (1) |
| Hi, how is 5.9nm obtained? |