Question #1117 | |
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Link to Question
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A 440/110 V single phase transformer supplies a load of 5 kW at 0.8 power factor load. What will be its primary current? | |
A) 45.45 A | |
B) 56.82 A | |
C) 14.2 A | |
D) 11.36 A |
Posted: 08 Oct 2015 00:31 UTC | Post #1 |
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maritimesailor Engine |
Member Total Posts: 4 |
I believe this answer is 11.36A | |
Posted: 29 Apr 2019 13:50 UTC | Post #2 |
Stan Engine |
Registered Total Posts: 4 |
P=I*U*load factor Correct answer is 14.2A |
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Posted: 29 Jan 2021 15:05 UTC | Post #3 |
scrubbyj427 Engine |
Member Total Posts: 7 |
can someone show the math to this? | |
Posted: 30 Jan 2021 02:47 UTC | Post #4 |
dracopolis Engine |
Member Total Posts: 5 |
P = 5000 W (5kW), V = 440 V, Load Factor = 0.8, P = I*V*Load Factor 5000 = I*440*0.8 I = 5000/(440*0.8) = 14.2 A |
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Posted: 10 Feb 2021 18:46 UTC | Post #5 |
scrubbyj427 Engine |
Member Total Posts: 7 |
Thank you DRACOPOLIS |
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